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How do you calculate the maximum possible Available Fault Current at the secondary of a Transformer?

Published date: 09 May 2018

Transformer Available Fault Current

Product Line
LV Transformers

Applies to LV Transformers by SquareD/Schneider Electric

Transformers are often connected to equipment that is rated for certain AIC, Average Interrupting Current, or Available Fault Current

Take the secondary full load current of the Transformer and divide it by the Transformer`s impedance. This is not necessary on Transformers below 15kVA, thus why UL does not require the impedance on the nameplate of Transformers below 15kVA. For example, a 75kVA Transformer with a 208Y/120 secondary and 5% impedance has a capacity of 208 amps on the secondary. The peak let through with an infinite source (worst case scenario) would have 208 / 0.05 = 4,160 amps of peak let through current (available fault current).


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